An analogue transformation is proposed for solving the axially symmetrical equation²ψ/R² - (1/R)ψ/R + ²ψ/z² = 0This consists of transforming the boundaries and coordinates by the rule R' = kR², z' = z and then solving the transformation using the normal resistive paper technique. A first order mathematical justification of the method is given and a comparison is made between the solutions obtained in certain cases and those derived by numerical relaxation methods. Agreement between these solutions is very satisfactory.