| dc.description |
Draw axes XOX′, YOY′. Draw graph of y = φ(t), taking OX as a positive axis of t. (In Figure see dotted line). Draw graph of x =f(t), taking OY′ as positive axis of t. (In Figure f(t) = t<sup>3</sup> – t<sup>2</sup>; see broken line). Take any point A in the line1+x = 0. Go along line through A parallel to OX till a point B a the graph x =f(t) is met, and vertically parallel to OY until a oint C in the graph y = φ(t) is met. The fourth vertex D of the ectangle ACDB is a point in the graph of the eliminant of t in he equations x =f(t), y = φ(t). |
